If steppers are run in series, the voltage per stepper drops off - supposedly to half.
But can that reduction be made up partially by increasing current for series steppers? (Assume the driver can deliver the current and that supply is 24V vs 12V)
Applying Ohms Law - likely way too simplistically - to the following example:
In parallel: 1A stepper, 2.5V, 2.5ohms (easy numbers to work with) Operating: 1A x 2.5V = 2.5W. So, 2.5W of heating power, the max the motor can take without overheating.
In series: Same steppers. Operating: (current the same in series circuit) 1A x1.25V (per motor with V divided across two motors) = 1.25W. So only half the heating power. The motor should be able to take a higher current
Can the stepper take up to almost 2A when in series? 2A x 1.25V = 2.5W, the same power load as it would see in the parallel example.
But can that reduction be made up partially by increasing current for series steppers? (Assume the driver can deliver the current and that supply is 24V vs 12V)
Applying Ohms Law - likely way too simplistically - to the following example:
In parallel: 1A stepper, 2.5V, 2.5ohms (easy numbers to work with) Operating: 1A x 2.5V = 2.5W. So, 2.5W of heating power, the max the motor can take without overheating.
In series: Same steppers. Operating: (current the same in series circuit) 1A x1.25V (per motor with V divided across two motors) = 1.25W. So only half the heating power. The motor should be able to take a higher current
Can the stepper take up to almost 2A when in series? 2A x 1.25V = 2.5W, the same power load as it would see in the parallel example.