My 12V PSU gave up and maybe it is time to increase the voltage.
I'm wondering. if I use 24V volts for motors and about 1A avg current with tmc2100 driver, do I really get double output from motor or what do I get?
Simple physics says F= BxI, where F is force, B is magnetic field and I is current. Also P = RI2 and again no voltage there. If the I is average and R is impedance which is defined by DC resistance and inductive impedance of the coil. The higher voltage is only increasing rise and fall times as it is driving harder the motor.
But does the magic inside tmc2100 compensate the increased rise time and I only get more heat when the current is the one ampere?
I know I must be somehow wrong and I didn't make the full calculations.
I'm wondering. if I use 24V volts for motors and about 1A avg current with tmc2100 driver, do I really get double output from motor or what do I get?
Simple physics says F= BxI, where F is force, B is magnetic field and I is current. Also P = RI2 and again no voltage there. If the I is average and R is impedance which is defined by DC resistance and inductive impedance of the coil. The higher voltage is only increasing rise and fall times as it is driving harder the motor.
But does the magic inside tmc2100 compensate the increased rise time and I only get more heat when the current is the one ampere?
I know I must be somehow wrong and I didn't make the full calculations.